Can some one debug it pls.. #include int main() { int one,two,ans=0; char sym; printf("Enter a number: "); scanf("%d/n",&"%d/n",&one); printf("Enter another number :"); scanf("%d/n",&two); printf("Enter an operator(+,-,*,/): "); scanf("%ch/n",&sym); if(sym=='+') ans=one+two; else if(sym=='-') ans=one-two; else if(sym=='*') ans=one*two; else ans=one/two; printf("The result is: ",ans); getch(); return 0; } It always show same result i.e -7188

Question

Can some one debug it pls..

#include<stdio.h>
int main()
{
int one,two,ans=0;
char sym;
printf("Enter a number: ");
scanf("%d/n",&"%d/n",&one);
printf("Enter another number :");
scanf("%d/n",&two);
printf("Enter an operator(+,-,*,/): ");
scanf("%ch/n",&sym);
if(sym=='+')
ans=one+two;
else if(sym=='-')
ans=one-two;
else if(sym=='*')
ans=one*two;
else 
ans=one/two;
printf("The result is: ",ans);
getch();
return 0;
}

It always show same result i.e -7188

anonymous · Answer

scanf("%d
", &"%d
", $one);   is this a typo?

anonymous · Answer

also scanf("%ch
", &sym); %c is the correct conversion specifier and not %ch :-(

anonymous · Answer

instead of that line, you can use sym = getchar()

anonymous · Answer

Finally, you've got printf("The result is: ", ans) with no %d conversion specifier in the format string.

anonymous · Answer

C is a lot complicated than C++. :P

anonymous · Answer

not really. It's just that scanf() is so inconvenient

anonymous · Answer

now it shows 4+4=1

anonymous · Answer

http://ideone.com/bTFbT

anonymous · Answer

hahaha I have a bug in there: one / 2 instead of one / two :-P

anonymous · Answer

http://ideone.com/xCtvs