Question

sqrt[8]{x-3}=sqrt[4]{x+2}?

Answer 1

square both sides and temme wut u get afta that

Answer 2

(x-3)^8=(x+2)^4??

Answer 3

\[{8(x-3)}^1/2={4(x+2)}^1/2\]

Answer 4

is it this way

Answer 5

\[\sqrt{8}(x-3)=\sqrt{4}(x+2)\] is this the question?

Answer 6

well if its what i wrote
then first u distribute the sqrt 8 and sqrt4
\[\sqrt8 x-3\sqrt8 = \sqrt4 x +2\sqrt4\]
but\[\sqrt8=\sqrt4 \times \sqrt2 =2\sqrt 2\]and\[\sqrt4 =2\]
so the equation becomes
\[2\sqrt2 x-(3 \times 2\sqrt2) = 2x+ (2 \times 2)\]\[=2\sqrt2 x -6\sqrt2 = 2x+4\]\[2\sqrt2 x-2x=4+6\sqrt2\]\[x(2\sqrt2 -2) = 4+6\sqrt 2\]\[x=\frac{4+6\sqrt2}{2\sqrt2 -2}\]

Answer 7

u just need to simplify now