Question

What are the possible number of positive real, negative real, and complex zeros of
f(x) = 6x3 – 3x2 + 5x + 9?
Answer:

A)Positive Real: 1
Negative Real: 0
Complex: 2

B)Positive Real: 2 or 0
Negative Real: 2 or 0
Complex: 1

C)Positive Real: 2 or 0
Negative Real: 1
Complex: 2 or 0

D)Positive Real: 1
Negative Real: 2 or 0
Complex: 2 or 0
Help me please:)))

Answer 1

+6x3 -3x2 +5x +9
1 | 1 | 0 |

sign changes twice, which means there is either 2 or 0 positives

swap the signs of the odd powers:

-6x3 -3x2 -5x +9
1 | 0 |

signs changes once; there is at elast 1 negative solution

Answer 2

id say its "c"

Answer 3

haha yeah i kinda got tht from you explaining it, thank you very much:)))

Answer 4

:) youre welcome