what is the limit as x approaches 3 on these two graphs? images attached.
what would/is the value at x=3?
graph 1 has a jump so the value from the left doesnt match the value from the right, no matchy, no limit
graph 2 is the is the same value from the left and the right at x=3, its limit is simply the value at x=3
if i add the two (DNE +3=DNE) my software doesnt accept my ans
why would you add them?
limx→3+[f(x)+g(x)]
thats the problem given to me, im supposed to determine the limit as x approaches 3 on both graph and perform that calculation
does it specify a direction?
oh yea sorry
from the right side
the value as x approaches 3 from the left or right?
from the right then is just the value of "hole" at x=3 as you follow the line from the right in graph 1 then
do you see that on graph1 the value is approaching y=3 from the right?
yes
since the right and left limits do not match there is no "limit" at x=3; but we can determine directional limits just fine
i wrote DNE and my software rejected the ans
dont write DNE then :)
limit from the right g1 = 3; g2 = 1
3+1 = 4
how is graph2= 1
what is the value of x=3 in g2?
its on the curve itself so it definantly has a limit
i see
thanks for the help can you help me with these two but first let me try to see if i understand 2. f(3)g(3) 3. f(3)+g(3)
f*g f+3
the values are the same if as before if we are limiting from the right
f*g f+g typoed myself
we are supposed to get the same ans? if so my software is saying different
not the same answer perse; but since the values of f(3) and g(3) dont change from problem to problem we dont need to refigure them out all over again
ok so what i perform (3) (1)= 3, my software says no
when*
from what youve written, thats what I would agree to
otherwise your notation is off
well it says f(3) g(3) and graph 1 is f, graph 2 is g
maybe its not talking about limits, but values?
yeah i think so
f(3) has a specific value, the dot itself
g(3) is still 1 no matter if its the limit or not :)
you were right. thanks for the help very much
youre welcome :)
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