Solving Square Root Equations
5(squareroot of)x-1=(squaredrootof) x+1

Question

dumbcow · Answer

square both sides

--> 25(x-1) = x+1

anonymous · Answer

yes, but i need to get x. :(

dumbcow · Answer

you can solve it from there
get x by itself

anonymous · Answer

it would be 25x? thats somethign i dont get.

anonymous · Answer

$$5\sqrt{x-1}=\sqrt{x+1}$$$$(5\sqrt{x-1})^{2}=(\sqrt{x+1})^2$$$$25(x-1)=x+1$$$$25x-25=x+1$$-x     +25    -x +25$$24x=26$$/24     /24$$x=$$

anonymous · Answer

i dont get the 5th step...

anonymous · Answer

The "-x  +25  -x  +25" step?

anonymous · Answer

wouldnt it be 24x-24=0?
yeah yhat step.

anonymous · Answer

No$$-25-1=-26$$

anonymous · Answer

wooow... feeling like a genius...

anonymous · Answer

If you moved both the x and 1 from the right side to the left you'd subtract -1 from a negative 25, making you go more negative.

anonymous · Answer

I hate making those simple mistakes.

anonymous · Answer

okay. so, if i also take the x out, because i want to have =0, it owuld be 24x-26=o, correct?

anonymous · Answer

Yes.

anonymous · Answer

so now i factor it, right?

anonymous · Answer

You shouldn't need to factor it.$$24x-26=0$$Should be the equation. Move -26 over to get$$24x=26$$Then divide to get the answer.

anonymous · Answer

:) whoops. Thanks.