Question

Solving Square Root Equations
5(squareroot of)x-1=(squaredrootof) x+1

Answer 1

square both sides

--> 25(x-1) = x+1

Answer 2

yes, but i need to get x. :(

Answer 3

you can solve it from there
get x by itself

Answer 4

it would be 25x? thats somethign i dont get.

Answer 5

\[5\sqrt{x-1}=\sqrt{x+1}\]\[(5\sqrt{x-1})^{2}=(\sqrt{x+1})^2\]\[25(x-1)=x+1\]\[25x-25=x+1\]-x +25 -x +25\[24x=26\]/24 /24\[x=\]

Answer 6

i dont get the 5th step...

Answer 7

The "-x +25 -x +25" step?

Answer 8

wouldnt it be 24x-24=0?
yeah yhat step.

Answer 9

No\[-25-1=-26\]

Answer 10

wooow... feeling like a genius...

Answer 11

If you moved both the x and 1 from the right side to the left you'd subtract -1 from a negative 25, making you go more negative.

Answer 12

I hate making those simple mistakes.

Answer 13

okay. so, if i also take the x out, because i want to have =0, it owuld be 24x-26=o, correct?

Answer 14

Yes.

Answer 15

so now i factor it, right?

Answer 16

You shouldn't need to factor it.\[24x-26=0\]Should be the equation. Move -26 over to get\[24x=26\]Then divide to get the answer.

Answer 17

:) whoops. Thanks.