The graph of which equation has a vertex of (3, 0)?

y = (x + 3)^2
y = (x - 3)^2 + 3
y = 2(x + 3)^2
y = 2(x - 3)^2

Question

The graph of which equation has a vertex of (3, 0)?

y = (x + 3)^2
	y = (x - 3)^2 + 3
	y = 2(x + 3)^2
	y = 2(x - 3)^2

anonymous · Answer

The answer is y = 2(x - 3)^2.

Quadratic Form y=a(x-h)^2+k
Vertex=(h,k)

anonymous · Answer

Given vertex is  = ( 3 , 0)

That is (h ,k) = (3,0)

standard form of  of parabola is

                   y = ( x- h)^2 + k

Plug (h , k) values in the parabola equation  [ h=3,k=0]

So we get         

                  y = (x - 3)^2 + 0

                  y = (x-3)^2