Question

When solving x^2 - 16x = 10 by completing the square what value is added to both sides of the equation?

6
8
16
64

Answer 1

64

Answer 2

x^2 -16x = 10

x^2 - 16x +(co-efficient of x/2)^2 =10 + (co-efficient of x/2)^2

Here , co-efficient of x is 16
So
x^2 -16x + (16/2)^2 = 10 + (16/2)^2

x^2 -16x + (8)^2 = 10 + (8)^2

x^2 - 16 + 64 = 10 + 64

Therefore both sides add by 64