Question

Integration

Question in comment, i don't know how to attach images in a question

Answer 1

oooops, i didn't mean dy/dx, i meant the integration sign

Answer 2

aah - i thought that might be the case

Answer 3

if there was the correct notification, would that be correct?

Answer 4

split this up into partial fractions
we get

INT (1 - 7 ) dx
-----
3(x+3)

Answer 5

can you continue from there?

Answer 6

you rresult is not correct

Answer 7

I don't understand what you have done, where has this 7 and this 3(x+3) came from?

Answer 8

sorry guy - i copied the question down wrongly - i'll hav e another look at it

Answer 9

ok, i was a bit worried when a 7 randomly appeared lol
thanks for helping me out, im currently revising for an exam :D

Answer 10

kind of a guess: is it this instead?

Answer 11

or...

Answer 12

first do long division to obtain

INT 1 / 3(3x + 1) + INT 1/3

= 1/3 INT 1/ (3x+1) + x/3

Answer 13

dividing 3x + 2 by 9x+ 3 gives 1/3 + 1 / (9x+ 3)

Answer 14

am i right?

Answer 15

must admit my integration is pretty rusty

Answer 16

lol, mine too, and i have an exam on it in about 36 hours xD

Answer 17

I thought that the question would involve natural logs when integrating (like when 1/x is integrated) doesn't it?

Answer 18

yes - so integrating 1/3 INT 1/ (3x+1) = 1/9 ln| 3x+1|

so finally answer is x/3 + 1/9 ln| 3x+1| + C

Answer 19

yea thats correct - i checked it out on wolframalpha

Answer 20

ok, thanks for your help :D

Answer 21

yw