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the smallest integral value of "c" that will produce imaginary roots in the equation 4x^2-7x+c=0 is (1) 1 (2) 2 (3) 3 (4) 4
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discriminant
b^2 - 4ac is less than 0,, then it would have imaginary roots
(-7)^2 - 4(4)(c) 49 - 16c < 0 49 < 16c 49/16 < c 3.0625 < c
would the answer be four then because 3.0625 is less than 0?
if you have this \[b^2-4ac<0\] then you have imaginary solutions
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\[(-7)^2-4(4)c<0\] money just solved this inequality
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