Could I find the two missing angle measures if I know some of the side lengths of a right triangle?
some means more than 1, right?
Yeah, I'm pretty sure
then with sine, cosine, tangent, you can find the angles
yes, by using SAS congruents and those stuff. like.. a^2 = b^2 + c^2 -2ab Cos A
im not really sure how to use them to find the angles instead of the other way around
a^2 = b^2 + c^2 -2ab Cos A
But if you know it's a right triangle, you don't use the cosine law
Better only use a² + b² = c²
Got it?
that'll help me find the sides, but i need the angles
sine theta = opposite/ hypotenuse cosine theta = adjacent / hypotenuse tangent theta = opposite/ adjacent
Pythagorean theorem does not help to find angles
Yeah
so how do i use the trigonometric ratios to find the angles if i only know the right angle?
im still confused xD
then you use inverse sine/cosine/tangent
okay, how do i use those? im a bit new at this
The sum of the interior angles of a triangle are equal to 180 degree. To find the third angle of a triangle when the other two angles are known subtract the number of degrees in the other two angles from 180 degree :)
i understand that, but i only know the 90 degree angle
Let me show you the example so that you will get it better. :)
@sweetrascal That has nothing to do with this
Example: How many degrees are in the third angle of a triangle whose other two angles are 40degree and 65degree ? Answer: 180degree - 40degree -65degree = 75degree
i only know the 90 degree angle... that's not what im looking for
\[\sin \theta = \frac{1}{2}\]\[\sin^{-1}\sin \theta = \sin^{-1} \frac{1}{2} \implies \theta = \sin^{-1} \frac{1}{2}\]
Moneybird will help you further :)
hmm
so both sides are multiplied by the inverse sine?
not multiplied on your calculator there is a inverse sine buton
okay, i get it! thank you!
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