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Mathematics 15 Online
OpenStudy (anonymous):

Please show your work and steps when you answer the following question: Determine the length of MN to the nearest tenth of a centimeter. Picture attached below :)

OpenStudy (anonymous):

OpenStudy (anonymous):

okay you need to know sin tan cos rules do you know them?

OpenStudy (anonymous):

yes can u show me step by step how to solve this specific problem. please thanks

OpenStudy (anonymous):

okay give me a little bit of time

OpenStudy (anonymous):

for sure. thank you

OpenStudy (anonymous):

are you guys figuring it out

OpenStudy (anonymous):

sorry i havent done geometry for a while but i got the first step done lol :/

OpenStudy (anonymous):

ok as long as you get it done its all good lol

OpenStudy (anonymous):

okay i think i got it but it could be wrong considering i havent done this in a while

OpenStudy (anonymous):

1st you would solve for cosine since you know the hyp and are looking for the adjacent \[\cos 33= x/8.2\] but you have to get rid of the 8.2 so you use inverse \[(8.2/1)\cos 33=x/8.2 (8.2/1)\] cancels the 8.2 on the side with te x and leaves you with the x and you get \[(8.2)\cos33\approx6.87=x\]

OpenStudy (anonymous):

|dw:1327040409127:dw| so then solve for the missing angle which ends up being 57

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