Question

plz help :)
list the possible zeros for the polynomial..

h(x)=2x^3+5x^2-31x-15

plz help :)

Answer 1

try factoring it first :)

Answer 2

oh. i see :( let me think :)

Answer 3

thank you!! :)

Answer 4

well...it is factorable: x (x (2 x+5)-31)-15. --> this gives you all the zeroes ;)
but you're right., it's not easily factorable.
graph it :). graphing calculator. otherwise there's nothing...really easy to see besides one

Answer 5

x (x (2 x+5)-31)-15 --- this is factor? :O

Answer 6

it's a ...kind of factor. not the kind you're thinking of ;)

Answer 7

No need to graph, if you know Newton-raphson or method of bisection.