Question

Solve for T: Equation below.

Answer 1

\[\sum_{j=0}^{4}\sin(k(xcos(\frac{2\pi j}{5})+ysin(\frac{2\pi j}{5}))-\omega T) = \sum_{j=0}^{4}\sin(k(xcos(\frac{2\pi j}{5})+ysin(\frac{2\pi j}{5})))\]

Answer 2

just realised that that isnt very visible. the other half of that equality is:\[\sum_{j=0}^{4}\sin(k(x\cos(\frac{2\pi j}{5})+y\sin(\frac{2 \pi j}{5})))\]