Question

How many moles of ethane (C2H6) would be needed to react with 62.3 grams of oxygen gas?

Unbalanced equation: C2H6 + O2 → CO2 + H2O

Answer 1

balenced equation is C2H6+5O2 yield 2CO2+3H2O

Answer 2

the balanced equation is 2(C2H6) + 7(O2) >>>> 4(CO2)+6(H2O)

Answer 3

If you do the stoichiometry you get an answer of 0.556 mol of ethane (C2H6)

Answer 4

(62.3gO2) * (1mol O2 / 31.998 g O2) * (2mol C2H6 / 7mol O2) = 0.566 mol ethane

Answer 5

with sig figs --> .389 mol C2H6

\[62.3g \space O_{2} \times 1mol O_{2} \times 4molC_{2} H_{6} \over 32.00g \space O_{2} \times 7mol \space O_{2}\]

Answer 6

@tktechie where did you get the 4 mol of C2H6 in your stoichiometry?

Answer 7

@ SalvatoreTRM Oh crud! That was a typo.. and the answer i gave was wrong, too. the answer was based off of the original balace that the asker gave. I didn't think to check it.