Question

Vx is the velocity of a particle moving along the x-axis as shown. If x = 2.0 m at t = 1.0 s,
what is the position of the particle at t = 6.0 s?

Answer 1

here is the graph

Answer 2

These are the answers they give me

+2.0 m
6.0 m
−1.0 m
−2.0 m
+1.0 m

Answer 3

find the area under the curve it'll give the total displacement
till t= 1 sec , the area under the curve is =(2-0)*1+1/2 (4-2)*(2-1)=3 units
it's given the particle was on x=2 units at t=1 so so it was on x=-1 at the starting
Let's find first the area of graph above x axis= 1/2 *(2-0)*(4-0)=4 units in +ve x -axis direction
area below the x -axis = 1/2 (6-2)(-2-0)=-4 units
so the total displacement will be -4+4=0
so it'll be at it's original position x=-1
option 3

Answer 4

thanks a bunch it worked

Answer 5

2+(5*vx)

Answer 6

please could any one tell me why x=-1