Question

Help please :D

Answer 1

I need help with part c

Answer 2

srry

Answer 3

mth3v4 Can you help me plz????

Answer 4

im not very good with marices but ill

"try"

Answer 5

okkiedokieee

Answer 6

it will probably take time
pulling books

Answer 7

lol Thanx

Answer 8

did u told me that question

Answer 9

sorry?

Answer 10

sorries
:(

Answer 11

dont know this 1

Answer 12

r u ok mth3v4

Answer 13

I apologize, I didn't know you wanted me to help with this question. I'm taking a look now.

Answer 14

thanks jemurray. I was busy fighting with someone on os

Answer 15

So it was fine lol

Answer 16

Okay, these are just asking for relatively simple verifications. Let me show you how to do the first one.

Answer 17

Jemurray3 and SamIam are typing replies…

Answer 18

ok i did the first two parts but let me see what u got i really need part c

Answer 19

Razor are you ok?

Answer 20

Oh, okay, well if you did the first two I won't bother :) Watch now:
\[ A^{-1}\cdot A = \frac{1}{5}(2I - A) \cdot A = \frac{1}{5}(2I\cdot A - A^2) \]
but since
\[A^2 -2IA + 5I = 0\]
as per the assumption, then
\[2IA - A^2 = 5I\]
so plugging that in yields
\[\frac{1}{5}(5I) = I \]
So that is in fact the proper inverse matrix.

Answer 21

Just processing it give me a sec :D

Answer 22

OHHHH GOTTTT ITTTTT Thankx jemurray :D

Answer 23

No problem :)

Answer 24

R u gonna be around fro much longer?

Answer 25

For a little while

Answer 26

ok i may be back :D