h(t)=cot t , itervals given, π/4,3π/4 finally got the equation written out, took me and while to figure it out, sorry. book answer is -4/pi but I have no idea how to set this up
set up for?
what does it mean "the answer is \[-\frac{4}{\pi}\]? there is no question, just a definition of a function \[h(t)=\cot(t)\]
average rate of change
oh that is a question!
sorry, duh
average rate of change:\[\frac{change. in. y}{change.in.x}\]from begining to end
\[\frac{h(\frac{3\pi}{4})-h(\frac{\pi}{4})}{\frac{3\pi}{4}-\frac{\pi}{4}}\]
\[\frac{cot(3pi/4)-cot(pi/4)}{3pi/4-pi/4}\]
latex is slowing me down lol
i can do the bottom: \[\frac{3\pi}{4}-\frac{\pi}{4}=\frac{\pi}{2}\]
can we factor out a cot up top?
lol, right
tanpi/4 = 1; flip for cot = 1 tan3pi/4 = -1; flip for cot = -1
-1-1 = -2 for the top
\[\frac{-2}{pi/2}=-\frac{4}{pi}\]
I swear math makes me seriously think I may be retarded, I just cant understand it. Very difficult for my 30 year old brain. LOL...
just wait till your my age :)
I hope I catch on fairly quickly because I have to pass this course.
Thank you both very much!!
30!! i never met anyone so old....
I know! Old as dirt! LOL, at least that is how Cal. makes me feel anyway, I should know this stuff :(
Sorry to jump in after 7months on this question, but I'm having trouble understanding how you factored out the cot for the top. I'm getting stuck at \[\cot(3\pi/4)−\cot(\pi/4)\] How did you arrive at 1 and -1 for the top? I plugged it into my calculator and it came up something like 0.01something.
i believe that 7 months ago that was a joke :) pi/4 radians is equivalent to 45 degrees. the tangent of an angle is the slope of the line that the radius makes with the positive x axis. the cotangent is just the inverse of the tangent. |dw:1346155666663:dw| tan(pi/4) = n/n = 1, the inverse of 1 is: 1 when we have three pi/4 s, we end up with a 135 degree angle; |dw:1346155817540:dw| as such; tan(3pi/4) = -n/n = -1, the inverse is: -1 -1 - (1) = -2
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