Can anyone do this??? The annual interest on a 19000 investment exceeds the interest earned on a 18000 investment by 204. the 19000 is invested at a .6% higher rater than the 18000. What is the interest rate of each investment?

Question

anonymous · Answer

i messed this up somehow let me start again

anonymous · Answer

ok. i'm quite confused

anonymous · Answer

yeah you should be because i was being stupid. let me start over

anonymous · Answer

ok

anonymous · Answer

put the rate of the 18000 investment at r
the rate of the 19000 investment is r+.006
we have to work with numbers, not percents

anonymous · Answer

then you know that the return on 18000 is 
$$18000\times r$$ and the return on 19000 is 
$$19000\times (r+.006)$$ and you know that the second one is $204 more than the first, so 
$$18000\times r +204=19000(r+.006)$$ now we can solve for  r

anonymous · Answer

$$18000r+204=19000r + .006\times 19000$$
$$18000r + 204=19000 r + 114$$
$$204-114=19000r -18000r$$
$$90=1000r$$
$$r=\frac{90}{1000}=\frac{9}{100}=9\%$$

anonymous · Answer

love to know where they got 9% interest , i would go invest there

anonymous · Answer

i have to have the interest for both. do i add or subtract .6%

anonymous · Answer

?