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find the equilibrium point of S(x)=3x^2-3x+38 and D(x)= 56-6x
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when supply = demand
it might be easier to subtract D(x) from S(x) and solve the quadratic
S(x)=3x^2-3x + 38 - D(x)= (-6x + 56) --------------------- 3x^2 +3x -18 = 0 3(x^2 +x -6) = 0
3(2) = 6 +x means +3-2 x=-(3,-2) = (-3,2)
since the - is prolly a spurious result and undoable in real life; id go x=2
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since 44=44 id say its good
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