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11mL of 1 mol/L NaCl and 8mL of 0.10 mol/L AgNO3 they react. Find theoretical yield.
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Can you figure out the balanced equation?
i did NaCl = AgNO3 -> NaNO3 + AgCl
NaCl + *
that's balanced^
alright now you have to find the limiting reagent can you do that?
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i did i got AgNO3 as the limiting
now how do i get the theoretical yield if the mole ratio is 1:1
Does it tell you what product to take it to? if not pick one
no its one of those questions where you just have to find theoretical yield :O
\[8 ml AgNO_3(\frac{0.10 mole AgNO_3}{1000 ml AgNO_3})(\frac{1 mole AgCl}{1 mole AgNO_3})(\frac{MM AgCl}{1 mole AgCl})=theoridcal yeild\] where i put in MM put the molar mass of AGCL and follow the steps and this should tell you the theoridical yeild
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