Question

What is the slope for the 1st four seconds of the journey. see attached graph.

Answer 1

sorry??

Answer 2

I am not familiar with trigonometry

Answer 3

leave all....slope is 2....thats it...

Answer 4

how??

Answer 5

y/x is slope... for 0 to 4 sec y=8 and x=4...so y/x=2

Answer 6

why teacher insisted we use the formula (x2-x) (y2-y)

Answer 7

leave all formulas...the best method it y/x....

Answer 8

I dont understand now y =8

Answer 9

why is y not 4

Answer 10

coz the line is starting from -4....
actually y means y2-y1....and x means x2-x1.....

Answer 11

one point on the graph is (4, 4) another is (2,0) you can use
\[\frac{4-0}{4-2}=\frac{4}{2}=2\] if you like

Answer 12

You said "why teacher insisted we use the formula (x2-x) (y2-y)"
look at your notes more carefully. The teacher said use
\[ slope= \frac{y_2 - y_1}{x_2 - x_1} \]
where you have 2 points on the line:
point1= \( (x_1,y_1) \)
point2= \( (x_2,y_2) \)

Can you find 2 points on the line that starts at t=0 and ends at t=4 ?
It looks like at t=0 d= -4, so in point format that is (0, -4)
At t= 4, it looks like d= +4, so another point is (4,4)
See Sat's post above on how to use the slope formula to get the answer