Question

I need help again.... I will post the image in a bit

Answer 1

i am confused

Answer 2

we have
\[ (x-3)(x+3)/x(x-5) * -x.(x-5)/(x^2-x-12). (x^2-8x+16)/(x-4)\]

Answer 3

my friend said its 3-x or -x+3

Answer 4

Answer: -x+3

Answer 5

factor x^2-x-12 as (x-4)(x+3)
x^2-8x+16 as (x-4)^2
\[ (x-3)(x+3)/(x)(x-5) * (-x)(x-5)/(x-4)(x+3) * (x-4)(x-4)/(x-4)\]

Answer 6

we get when we remove the common terms from numerator and denominator
\[(x-3)(-1)\]
or \((3-x)\)

Answer 7

your confusing the person.. -_-

Answer 8

with different answers

Answer 9

dead retrice-_-

Answer 10

retrice

Answer 11

lolol
not to be mean

Answer 12

sorry you're right

Answer 13

my answer is right. - Nikki x <3 (: