Question

For what value(s) of x is √(– x)^2 = –| x |?
A. x ≤ 0
B. x = 0 only
C. x ≥ 0
D. no values of x

Answer 1

B.

Answer 2

Interesting...... my take is D.

Answer 3

But I am not sure. The right hand side -|x| will always be negative. The left hand side will be positive unless we are recognizing the negative root (which I am willing to do).

Answer 4

\[\sqrt{-(0)^2}=-|0| \text{ is true}\]

Answer 5

I agree with B

Answer 6

Told you :)

Answer 7

Lets do a trial. Let x=-1, then \[\sqrt{(-(-1))^{2}}=-|-x|\]\[\pm1=-1\] I guess this is not totally true. Forget d

Answer 8

but I can't forget it entirely lol

Answer 9

radar is definitely works for x=0

Answer 10

it*

Answer 11

Yes b is for sure, I was trying to eliminate a c and d.

Answer 12

\[\sqrt{(-x)^2}=|-x| \]

Answer 13

I guess\[\pm0=-|0| \] is definitely true.

Answer 14

\[|-x|=-x \text{ if x<0} ; |-x|=x \text{ if x>0}\]
hey hershey calm down
just because you are confident in you answer doesn't mean everyone is

Answer 15

Thanks all, I am convinced B is correct.

Answer 16

good job though hershey

Answer 17

:)

Answer 18

The other distractors (a, c, and d) truly distracted me lol

Answer 19

Radar try writing them both as a piece wise function.

Answer 20

Ok, lol

Answer 21

Yes I see it, the double negative when a x<0 was substituted on the left was confusing me.

Answer 22

The fact that the total was being squared, then the square root was to be taken. The right hand side was straight forward for me. Thank goodness, I have passed the test taking phase of my life lol.

Answer 23

lol
This is the way I looked at it
\[\sqrt{(-x)^2}=|-x|=|-1||x|=1|x|=|x|\]

Answer 24

\[|x|=-|x| \text{ when x=0 only}\]

Answer 25

Yes that makes it most obvious to the casual observer (like me)

Answer 26

I was thinking about doing this a longer way, but this is the most easiest way

Answer 27

Yes that does simplify it.

Answer 28

if you wouldn't mind i posted another question i need help with