Question

(a^-1)-(b^-1)
------------
(b^-2)-(a^-2)

Answer 1

the line is divide

Answer 2

\[\frac{\frac{1}{a}-\frac{1}{b}}{\frac{1}{b^2}-\frac{1}{a^2}}\] multiply top and bottom by
\[a^2b^2\] get
\[\frac{ab^2-a^2b}{a^2-b^2}\]
\[\frac{ab(b-a)}{(a-b)(a+b)}\] and finally
\[-\frac{ab}{a+b}\] since
\[\frac{b-a}{a-b}=-1\]

Answer 3

Thanks

Answer 4

So the answer is -1?
Also how did you get from the second to last step to the last step?