Question

--->>>Problem #8

Answer 1

Why is the answer not 14?

Answer 2

i did 142-2/10-0 = 140/10 = 14

Answer 3

\[f(t)=t ^{2}+4t+2 \therefore f(t)\prime=2t+4\]

Answer 4

???

Answer 5

you differentiate f(t)

Answer 6

o wait

Answer 7

i plugged in 10 but i wasnt supposed to, right?

Answer 8

yep

Answer 9

just 0 and t

Answer 10

no, find the zeroes of the first function f(t) leaving you with \[t=-2-\sqrt(2) , \sqrt(2)-2\]

Answer 11

im kinda confused

Answer 12

can you show work please

Answer 13

\[2t+4=10 \therefore t=3\] i think

Answer 14

im getting even more confused... i dont think we've covered what you are doing in my class yet

Answer 15

have you done differentiation ?

Answer 16

dont think so? if we have, i must've been day dreaming or something

Answer 17

ouch! not a good thing to solve calculus if you haven't done it before you'll just be hurting your mind

Answer 18

the answers not 3 btw

Answer 19

yh, what was it ?

Answer 20

idk yet, you tell me lol

Answer 21

what are the options then ?

Answer 22

no options

Answer 23

it just tells you if you got it right or wrong

Answer 24

shoot!

Answer 25

at least i get unlimited tries lol

Answer 26

since y=mx+c then f(t)'=2t+4

Answer 27

its 6

Answer 28

the answer is 6

Answer 29

i do just plug in 0 and t and then do rate of change

Answer 30

alryt, show me wh@ you did ?

Answer 31

we are all learning

Answer 32

f(0)^2+4(0)+2=2
f(t)=t^2+4t+2

t^2+4t+2-(2)/t
=t+4
t=6 because 6+4 is 10 (10 is given in the problem)

Answer 33

alryt, i see. why did you divide thru by t ?

Answer 34

its usually by h but since there is no h i made it a t (im using the difference quotient formula or whatever its called)

Answer 35

alryt, so you haven't done calculus before ?

Answer 36

first time

Answer 37

awesome!

Answer 38

why is that? lol

Answer 39

yh, coz you haven't done calculus yet and you did a calculus problem, so th@s awesome

Answer 40

lol

Answer 41

i posted another question that you could maybe help me with

Answer 42

alryt, i'll try wish me luck