Question

i got the wrong answer again...

Answer 1

its not 13 btw

Answer 2

\[f(t)=\frac{1}{t} , \text{ from 1 to t} AVRC=\frac{-1}{6} \]

Answer 3

is that right?

Answer 4

\[AVRC=\frac{\frac{1}{t}-\frac{1}{1}}{t-1}=\frac{-1}{6}\]

Answer 5

\[\frac{t}{t} \cdot \frac{\frac{1}{t}-1}{t-1}=\frac{-1}{6}=> \frac{1-t}{t(t-1)}=\frac{-1}{6}\]
\[\frac{-(t-1)}{t(t-1)}=\frac{-1}{6} => \frac{1}{t}=\frac{1}{6} => ?\]

Answer 6

thats a fill in the blank question i left behind for you
if 1/t=1/6 then t=what

Answer 7

THANKS

Answer 8

what about prob 10 though?

Answer 9

o i took a snapshot of the wrong problem -_-

Answer 10

ok this is the right prob 10

Answer 11

\[(5A ^{2}-5)/(A-1)=60\]

Answer 12

then?

Answer 13

ive done that but i havent gotten the right answer

Answer 14

\[A= \sqrt{23}\]

Answer 15

how did you get that?

Answer 16

solve for a

Answer 17

thats wrong -_-

Answer 18

x intervals from (1,A) ryt ?

Answer 19

yes

Answer 20

305, 13, and square root of 23 are not the answers

Answer 21

ah, I can't read these .xlsx documents on this computer. Sorry.

Answer 22

ill type it out then

Answer 23

Let f(x)=5x^2. Find a value A such that the average rate of change of f(x) from 1 to A equals 60.

Answer 24

\[5(a-1)(a+1)/(a-1) =60\]

Answer 25

A=11