Question

√c (3 + 2√5) and √6 (7√3 + 6) Please help???

Answer 1

is that a c in front?

Answer 2

its asking for the square root of 3 then(3+2√5) and then the other question

Answer 3

@ satellite

Answer 4

The left :/

Answer 5

):

Answer 6

What are we suppose to do here?

Answer 7

Multiply and Simplify

Answer 8

Multiply/Distribute in this case, and simplify

Answer 9

I got the first one, just need help with the second

Answer 10

Y dont you retype the question?

Answer 11

It isnt so clear

Answer 12

\[\sqrt{3} (3+2 \sqrt{5}) \sqrt{6}(7 \sqrt{3}+6)?\]

Answer 13

we are finding product right?

Answer 14

\[√6(7√3 + 6)\] thats the one i still need help on

Answer 15

myinaya it itwo separate equations

Answer 16

distributing and simplifying

Answer 17

\[\sqrt{6}(7 \sqrt{3}+6)\]

Answer 18

\[\sqrt{6} \cdot 7 \sqrt{3}+\sqrt{6} \cdot 6 \]

Answer 19

i use distributive property there

Answer 20

a(b+c)=ab+ac

Answer 21

\[7 \sqrt{6} \sqrt{3}+6 \sqrt{6}\]
\[7 \sqrt{2 \cdot 3} \sqrt{3}+6 \sqrt{6}\]

Answer 22

\[7 \sqrt{2} \sqrt{3} \sqrt{3}+6 \sqrt{6}\]

Answer 23

is the "c" a "3"??

Answer 24

\[7 \sqrt{2}(3)+6 \sqrt{6}=7(3) \sqrt{2}+6 \sqrt{6}=21 \sqrt{2}+6 \sqrt{6}\]

Answer 25

\[ \sqrt{6}(7 \sqrt{3}+6) = 21\sqrt{2} +6\sqrt{6} \]

Answer 26

Thank you guys so much!!

Answer 27

Distributive property holds because they are rationals.