Question

Factor binomial: 64x^3-1. How do i do this with a x^3 I dont understand :(

Answer 1

\[64x^{3}-1\]

Answer 2

Hi starshine7!

Here we can use the formula, \[a ^{3}-b ^{3}=(a-b)(a ^{2}+ab+b ^{2})\]
hence,
\[(8x)^{3}-(1)^{3}\]
Now can you do it by yourself?

Answer 3

It is \[ (4x)^3 - (1)^3 \]

Answer 4

\[(4x-1)(\ (4x)^2+(4x)(1)+(1)^2) \]
\[(4x-1)(16x^2+4x+1)\]

Answer 5

oh yes 4 not 8. thanx diyadiya

Answer 6

np :)