2 log base 3 sq.root. 27 ?!?!!?!?!?!!??!

Question

anonymous · Answer

2 x logbase3(sqrt(27))?

anonymous · Answer

$$2 \log _{3} \sqrt{27}  $$

anonymous · Answer

i dont understand it

anonymous · Answer

log base 3 of radical 27 is basicaly saying 3 to the what power = sqrt(27)

anonymous · Answer

and i don't understand logs in general

anonymous · Answer

but theres a 2 in front..

anonymous · Answer

you multiply by two after you get the first part

anonymous · Answer

its just multiplication in front

anonymous · Answer

do u mind drawing this out ? sorry I'm really stupid :(

ash2326 · Answer

$$2 log_{3} (\sqrt {27})$$
x=log y to the base b
means
b^x=y

anonymous · Answer

we actually just did this stuff today and yesterday in math class

anonymous · Answer

uh oh...maybe you're in my math class lol ...

ash2326 · Answer

and we have the property
c log y= log y(^c)

anonymous · Answer

lol, do you have algebra 2 im guessing?

anonymous · Answer

nope...im still very confused about the 2 in front though...this whole thing makes no sense to me

anonymous · Answer

the two in front is just multiplication, its like y = 2x, the two is multiplied

ash2326 · Answer

now 
$ 2 \log_{3} (\sqrt{27})$
$\log_{3}{(\sqrt{27})}^2$
$\log_{3} 27$
we know that 3^3=27
so
it's
$\log_{3} 27=3$

anonymous · Answer

not sure what the guy above me is doing. How are you squaring the radical 27?

anonymous · Answer

i am literally so confused

anonymous · Answer

well, whatever he is doing is right.

anonymous · Answer

the answer is 3

ash2326 · Answer

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