Question

show steps please
Solve the system by using elimination or elimination with multiplication.
x - y = 3 and x + y = 7
Solve the system by using elimination or elimination with multiplication.
2x + 3y = 12 and 3x + 2y = 13

Answer 1

x-y=3
x+y=7
Add them(elimination)
2x=10
x=5
x-y=3
y=2
(5,2)

Answer 2

first u need to find the value of either x or y
example:
x - y = 3 and x + y = 7

x - y=3
x =3+y
or
y = x-3

Answer 3

is (5,2) he anwser for the first one?

Answer 4

yep!

Answer 5

try to do the second one urself

Answer 6

2x+3y=12
3x+2y=13
multiply the first one by -2. multiply the second one by 3.
-4x-6y=-24
9x+6y=39
5x=15
x=3
Use this hint above if you need it :)

Answer 7

3, 2?

Answer 8

good!

Answer 9

Solve the system by using elimination or elimination with multiplication.
x + y = 16 and x + y = -2
is this one no solution?

Answer 10

yeah

Answer 11

3x - 2y = 9 and -3x + 2y = -9
and is this on no solution or infinte solutions??

Answer 12

notice if you eliminate it, there's nothing left

Answer 13

k thanks so much. thats what i thought. ya just making sure.

Answer 14

the last one you asked is infinite

Answer 15

they're the same thing

Answer 16

ok good thats what i thought!
not on hw they arent lol

Answer 17

haha true :P

Answer 18

\[6\sqrt{2}-3\sqrt{2}\]

Answer 19

3 sqrt 2

Answer 20

haha i already got it :p this one is hard. one sec.

Answer 21

\[5\sqrt{3}+8\sqrt{3}-6\sqrt{2}+4\sqrt{2}\]

Answer 22

13 sqrt3 -2 sqrt 2

Answer 23

lol, is this school hw?

Answer 24

ya

Answer 25

how did you get that?

Answer 26

\[\sqrt{2 } =x \]
\[\sqrt{3} = y\]

5y+8y -6x+4x= 13y -2x
and u will get :
\[13\sqrt{3}-2\sqrt{2}\]

Answer 27

that is the easier way to understand it