Question

Convert the equation 5x^2+5y^2=3y from a rectangular equation to a polar equation

Answer 1

by rectangular do you mean a+jb

Answer 2

complete the square

Answer 3

\[r<\theta \] ?

Answer 4

r = sqrt(x^2+y^2) stuff

Answer 5

x = r cos(..)
y = r sin(...)

Answer 6

5x^2+5y^2-3y=0

5(x^2) +5(y^2-3/5 y) = 0

5(x^2) +5(y^2-3/5 y +(9/25)) = 5(9/25)

5(x^2) +5(y-3/25)^2 = 5(9/25)

x^2 + (y-3/25)^2 = 9/25

Answer 7

looks like r = 3/5 in this case

Answer 8

\[(\frac{3}{5},\frac{3}{5}sin(t))\] maybe?

Answer 9

http://www.wolframalpha.com/input/?i=5x%5E2%2B5y%5E2-3y%3D0

http://www.wolframalpha.com/input/?i=polar+%283%2F5%2C+3sin%28t%29%2F5%29

seems to be a match