Question

need couple a work checks if no one minds...
Simplify:
(4y+7)^{2} = 16y^{2}+49

x^{2}+4x-2(5x^{2}-x+3) = -9x^{2}+6x-6

7-3(x+4)=8(x-1) --> x=3/11

Answer 1

(4y+7)^2=42y^2+72=16y^2+49

x^2+4x−2(5x^2−x+3)=x^2+4x−10x^2+2x−6=−9x^2+6x−6

solve:
7-3(x+4)=8(x-1) --> 7-3x-12=8x-8 --> -3x-5=8x-8 --> -11x=-3 --> x=3/11

that my calculations, just need a confirmation if possible, thank you
one second ago

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Answer 2

\[(4y+7)^2=(4y+7)(4y+7)=16y^2+56y+49\]

Answer 3

thank you

Answer 4

yw