Question

few question about e

Answer 1

1/(e^kt) = e^-kt ?, where as k is a constant

Answer 2

this is the laws of exponents.
\[b^{-n}=\frac{1}{b^n}\]

Answer 3

so, e^(kt)t=e^(kt)A+C, solving for t, u get t=e^(-kt)A+e^(-kt)C ?

Answer 4

e^(kt)T=e^(kt)A+C, solve for big T,

Answer 5

hold the phone. what are you solving here? it is always the case that
\[\frac{1}{e^{kt}}=e^{-kt}\]

Answer 6

got cha, thanks