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Mathematics 22 Online
OpenStudy (anonymous):

few question about e

OpenStudy (anonymous):

1/(e^kt) = e^-kt ?, where as k is a constant

OpenStudy (anonymous):

this is the laws of exponents. \[b^{-n}=\frac{1}{b^n}\]

OpenStudy (anonymous):

so, e^(kt)t=e^(kt)A+C, solving for t, u get t=e^(-kt)A+e^(-kt)C ?

OpenStudy (anonymous):

e^(kt)T=e^(kt)A+C, solve for big T,

OpenStudy (anonymous):

hold the phone. what are you solving here? it is always the case that \[\frac{1}{e^{kt}}=e^{-kt}\]

OpenStudy (anonymous):

got cha, thanks

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