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f(x)=1/2(x+5)^2+5: find the vertex, line of symetry and the max/min
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vertex is \[(-5,5)\] because this is in the form \[f(x)=a(x-h)^2+k\] so you can read off the vertex from the equation
since the leading coefficient is positive, this is a parabola that opens up, so it has no maximum but the minimum is the second coordinate of the vertex, namely 5
axis of symmetry is what you get when \[(x-5)^2=0\] namely \[x=5\]
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