Question

The absolute maximum value of f(x)=x^3-3x^2+12 on [-2, 4] occurs at x=

Answer 1

0

Answer 2

how?

Answer 3

That's Hard. D:

Answer 4

thanks for trying :))

Answer 5

No problem.
u may come here in a hour or two, user Myininya, Satellite, JamesJ and others are online. They can help u with this in Notime.

Answer 6

alrighty :)

Answer 7

C ya, nice meeting u! [:

Answer 8

pleasure was all mine :)

Answer 9

;)

Answer 10

x^3-3x^2+12 (1) first we determine the degree: (the maximum power at which x is raised::)
=> http://en.wikipedia.org/wiki/Polynomial#Graphs
then we find the derivative => 3x^2-6x (2)
then we see where (2) is zero /and we know that (1) has either a max, a min, or a change of heart there( see x^3)