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Mathematics 20 Online
OpenStudy (anonymous):

Factor the polynomial by factoring out the greatest common factor.

OpenStudy (anonymous):

\[(x^3-y)^2-(x^3-y)\]

OpenStudy (rogue):

What is the greatest common factor?

OpenStudy (rogue):

It would be (x^3 - y). So when you factor that out of each term, you divide each term by that.

OpenStudy (rogue):

\[(x^3-y)^2-(x^3-y) = (x^3 - y) (\frac {(x^3-y)^2}{(x^3 - y)} - \frac {(x^3-y)}{(x^3-y)})\]

OpenStudy (rogue):

\[(x^3-y)^2-(x^3-y) = (x^3 - y)(x^3 - y - 1)\]

OpenStudy (anonymous):

so that is the answer the last part or do i need to reduce it further.

OpenStudy (rogue):

That is the answer.

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