Question

Solve compound inequality. Write solution in interval notation. x+9<0 or 2x> -12 (these kill me)

Answer 1

it has no solution

Answer 2

x cant be grater than -6 and smaller than -9

Answer 3

Jmallis it's easy, if we proceed step by step
Let's solve the first equation
x+9<0
subtract 9 from both sides
x<-9
so x is \((-\infty,-9)\)
now from the second equation
2x>-12
or
x>-6
so from this equation x is \((-6, \infty)\)
now it's given x+9<0 or x>-12
so we have to take union of the two
ie x belongs to \((-\infty,-9)\) U \((-6, \infty)\)

Answer 4

Thank-you, you think you can help me with another one ash2326

Answer 5

yeah jmallis, post your question :)

Answer 6

Jmallis , post your question as a new thread, that way you can get more people to respond:)

Answer 7

\[-6\le2x-12\]\[\le18\]

Answer 8

should be all together

Answer 9

we have
-6<=2x-12<=18
add 12 to all sides
6<=2x<=30
divide be 2 the whole inequation
3<=x<=10
As we can see x belongs to [3, 10]
do notice that it's closed interval

Answer 10

says to solve compund inequality written in compact form, get x alone in the middle part. Since a compound inequality is really two inequalities in one statement, perform same operations on all 3 parts of inequality

Answer 11

Yeah , that's what I've done, notice I have added 12 to all three simultaneously, and divided by 2 all together.

Answer 12

When I put in [3,10] my homework page had a spaz attack

Answer 13

sorry I made a mistake
see this
we have
-6<=2x-12<=18
add 12 to all sides
6<=2x<=30
divide be 2 the whole inequation
3<=x<=15
As we can see x belongs to [3, 15]
do notice that it's closed interval
It won't get a attack now:D

Answer 14

It's fine now haha