Question

A student has 11 writing implements: 6 pencils, 4 ball point pens, and 1 felt tip pen.
The student can select 6 writing utencils in 462 ways.
In how many ways can the selection be made if no more than one ball point pen is selected?_____
Anyone know how to solve this

Answer 1

Student has 6 ball point pens, 4 ball point pens and 1 felt tip pin.
We have to find the no. of ways when he can select no more than 1 ball point pen.
No. of ways when he has to select 1 pen and 5 other utensils= 6C1*5C5=30 ways

Answer 2

Did you get it cwhutche?

Answer 3

it wasnt right

Answer 4

still isnt correct

Answer 5

it has beat me

Answer 6

I think I see my error.

Answer 7

do ya i still cant figure this out

Answer 8

Zero or one ball point pens will be chosen. There are C(4,0) times C(7,6) = 7 ways to choose 6 writing instruments that are not ball points. [Choose none of the ball points and 6 of the other 7.] There are C(4,1) times C(7,5) ways to choose 6 writing instruments, exactly one of which is a ball point pen .[Choose one of the ball points and 5 of the others.] There are, then, (4) (21) = 84 ways to choose 1 ball point and 5 others. That gives 7 + 84 = 91 ways to choose 6 writing instruments, at most one of which is a ball pen. answer: 91

Answer 9

What about now, CW?

Answer 10

That is it man....
awesome I appreciate it

Answer 11

yw. Sorry for my arithmetic errors early on.

Answer 12

no problem i made a million of them and had no clue i appreciate your time on this problem very much