What are the possible number of negative zeros of f(x) = –2x^7 + 2x^6 + 7x^5 + 7x^4 + 4x^3 + 4x^2 ?
Answer:
A)4, 2, or 0
B)2 or 0
C)3 or 1
D)7, 5, 3, or 1

Question

What are the possible number of negative zeros of f(x) = –2x^7 + 2x^6 + 7x^5 + 7x^4 + 4x^3 + 4x^2 ?
Answer:
A)4, 2, or 0
B)2 or 0
C)3 or 1
D)7, 5, 3, or 1

mertsj · Answer

Find f(-x) first.  Can you do that?

mertsj · Answer

It is very difficult to help you if you won't answer me.

anonymous · Answer

sorry im trying to multi-task

anonymous · Answer

and idk how to find f(-x):/

mertsj · Answer

replace every x with -x

anonymous · Answer

so you would subtract everything?

anonymous · Answer

2) f(x) = 2x^7 + 2x^6 + 7x^5 + 7x^4 - 4x^3 + 4x^2

f(-x) = -2x^7 + 2x^5 - 7x^5 + 7x^4 + 4x^3 + 4x^2

There are 3 changes of sign in f(-x), which means there can be possibly either 3 negative zeros or just 1 negative zero.

So the answer would be B.

anonymous · Answer

Sorry, C

mertsj · Answer

$$f(-x)=-2(-x)^7+2(-x)^6+7(-x)^5+7(-x)^4+4(-x)^3+4(-x)^2$$

mertsj · Answer

Ok  kdwndr wants to help you now.  Good bye.

anonymous · Answer

Thank you:)