Question

A 132 kg satellite experiences a gravitational force by the Earth of 760 N. What is the radius of the satellite's orbit?

Answer 1

There is a law called "Newton's law of universal gravitation" which states that the gravitational force between 2 objects is proportional to to the product of their masses and a constant G and inversely proportional to the square of the distance between them (their centers of mass), or : \[\ F= G \frac{m_1m_2}{r^2}\]

where
F- force between them(given)
G - gravitational constant (given, I will assume it is, since you know it is earth)
m_1- mass of the satellite(given)
m_2 - mass of the Earth (also assuming it is given)
r- distance between the center of earth and the satellite (this is what you need)

Solve above equation for r and plug in the values.

Answer 2

thanks!