Question

Find the integral of:

2x/3 sin(3x^2) dx

Answer 1

Take 2/3 out of the integral and integrate x/sin3x^2 which is = 1/6(log(sin(3x^2/2)))-log(cos93x^2/2)))+c

Answer 2

Oops, I meant for there to be brackets around the 2x/3 - I get the idea though, thanks :)