Question

f(x) = 1/(x^5-4 x).

Then f' =

Answer 1

f'= derivative of first times second minus derivative of second times first divided by the whole thing squared.

Answer 2

\[f(x)=\frac{1}{x^5-4x}\]We need to use the quotient rule...\[f'(x)=\frac{(x^5-4x)(0)-(1)(5x^4-4)}{(x^5-4x)^2}=\frac{5x^4-4}{(x^5-4x)^2}\]

Answer 3

what else do i need to do after that?

Answer 4

That's it. That's the derivative of f(x).

Answer 5

or f ' (x) =[ (4 - 5 x^4)] / [x^2 (x^4 -4) ^2]

Answer 6

Directrix is right. I forgot to distribute through the -1.

My answer was wrong.