Question

How can you write the following using a radical sign and no negative exponents?
1. 3y^(2/5)
2. (3y)^(2/5)
3. a^(4/7) * b^(-4/7)
4. a^(1/10) * b^(-1/5)

Answer 1

\[3\sqrt[5]{y^2}\] is the first one

Answer 2

second is
\[\sqrt[5]{3y^2}\]

Answer 3

explanations would be great if possible

Answer 4

1.)\[\ 3 \sqrt [5] {y^2}\]2.)\[\sqrt [5] {9y^2}\]3.)\[\sqrt [7] {a^4} * \sqrt [7] {\frac{1}{b^4}}\]4.)\[\sqrt [10] {a} * \sqrt [5] {\frac{1}{b}}\]

Answer 5

Here's an explanation for the first...
\[3y^{2/5}=3*y^{2/5}\]Since the following is true...\[y^{1/5}= \sqrt [5] {y}\]The first statement is the same as...\[3*y^{1/5}*y^{1/5}=3*\sqrt[5]{y}*\sqrt[5]{y}=3\sqrt[5]{y^2}\]Does that make sense?

Answer 6

yes! thank you:P