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Mathematics 14 Online
OpenStudy (anonymous):

simplify 6m/8n x 2n^2/3m

OpenStudy (anonymous):

n/2

OpenStudy (anonymous):

thanks but ... how did you get that? :S

OpenStudy (anonymous):

Let's start off by multiplying the two terms together. We get: (6)(m)(2)(n^2) / (8)(n)(3)(m) Grouping the numbers together: 12(m)(n^2) / 24 (m) (n) Since there is only one m in the numerator and denominator, we can cancel them out, getting: 12(n^2)/24(n) Dividing 12/24, we get 1/2 (n^2)/2(n) We can rewrite n^2 as (n)(n), and now we can cancel one n, getting: n/2

OpenStudy (anonymous):

OOOOH ! okay THANK YOU ! :)

OpenStudy (anonymous):

No problem :)

OpenStudy (anonymous):

this goes the same for 2rs/5st \[\div\]6rt/10s right? i just make it 2rs/5st x 10s/6rt then simplify that?

OpenStudy (anonymous):

Yup!

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