Question

PLEASE HELP Solve the given equation! 8^2x=11

Answer 1

x=11/64

Answer 2

Okay so, since neither the base nor the exponent is same, we take log
log8^2x = log11
By rule of log,
2x.log8=log11
Or, 2x=log11/log8
So, 2x=1.153
x=1.153/2
x=0.576

Answer 3

i would use this fact
\[b^x=A\iff x=\frac{ln(A)}{\ln(b)}\] to write
\[2x=\frac{\ln(11)}{\ln(2)}\] then divide by 2