Question

Can someone how to do 3^3/2 by hand?

Answer 1

explain**

Answer 2

or any x^(y/z)

Answer 3

is that
\[3^{3/2}\] or\[(3^3)/2\]

Answer 4

the first one.. 3^(3/2)

Answer 5

so its really (3^3)^1/2 so do the inner part 1st

(27)1/2

\[\sqrt{27}\] \[\sqrt{27}=\sqrt{9 \times3} =\sqrt{3^2 \times 3} = 3\sqrt{?}\]

Answer 6

oops ? = 3

Answer 7

3sqrt3?

Answer 8

\[\ 3^\frac{3}{2}\sqrt{3^3}=\sqrt{9}=3 \]

Answer 9

3^ 3/2
= surd 3^3

used, indices law..
surd 3^3 = surd 27

\[\sqrt{27}\]
= \[\sqrt{(9)(3)}\]
= \[3\sqrt{3}\]

Answer 10

So what if it was 3^5/3?

Answer 11

\[\ \sqrt{27}=\sqrt{\text{9 x 3}} = \sqrt{9} \text{ x } \sqrt{3}= 9\sqrt{3} \]

Answer 12

I'm so slow at latex :(

Answer 13

\[\huge \sqrt[n]{A^b}=A^\frac{b}{n}\]

Answer 14

for 3^(5/3)
= \[\sqrt[3]{3^5}\]
= \[\sqrt[3]{243}\]
= \[\sqrt[3]{(27)(9)}\]
= \[3 \sqrt[3]{9}\]

Answer 15

\[\huge note \ that \ \sqrt[2]{A}=\sqrt{A} \]