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Mathematics 22 Online
OpenStudy (anonymous):

If ~q <=> ~p is T and pf is F, find the truth value of q =>p.

OpenStudy (amistre64):

another way to express that <=> part is to split it up both ways: -q -> -p -p -> -q

OpenStudy (amistre64):

-q <-> -p is only true if bith those expressions are true

OpenStudy (anonymous):

I meant to say *and p is F. Sorry. So will the value be false?

OpenStudy (amistre64):

dunno, id have to remember all the assorted details :)

OpenStudy (anonymous):

don't you love truth tables?

OpenStudy (amistre64):

p -p q -q -p -> -q -q -> -p -q <-> -p 1 0 1 0 1 1 1 1 0 0 1 1 0 0 0 1 1 0 0 1 0 0 1 0 1 1 1 1 aint that the truth :)

OpenStudy (amistre64):

if p is 0 then -p is 1

OpenStudy (amistre64):

other than that, im sure I cant undersatnd the rest of the question

OpenStudy (anonymous):

we also have \[\lnot p \leftrightarrow \lnot q \equiv p \leftrightarrow q\]

OpenStudy (anonymous):

which certainly means if \[\lnot p \leftrightarrow \lnot q \] is true then \[q\rightarrow p\] is true

OpenStudy (amistre64):

If ~q <=> ~p is T p -p q -q -p -> -q -q -> -p -q <-> -p 1 0 1 0 1 1 1 0 1 0 1 1 1 1 and p is F, p -p q -q -p -> -q -q -> -p -q <-> -p 0 1 0 1 1 1 1 find the truth value of q =>p. p q -q <-> -p 0 0 1 0 -> 0 = 1

OpenStudy (anonymous):

wow! but i still think the question is odd. if p iff q, then q implies p and p implies q, really has nothing to do with a particular case

OpenStudy (amistre64):

indeed, its just a practice drill :)

OpenStudy (anonymous):

Wow. Thanks for breaking this down. My prof doesn't go this in-depth. Guess he gets bored since he already knows this stuff haha

OpenStudy (amistre64):

im in calc 3 and my teacher is still teaching us ow to add and subtract fractions; since there are students in class that have no idea how to .... makes me wonder how they even got there to begin with

OpenStudy (amistre64):

then she wonders why she gets behind in the lessons plans :)

OpenStudy (anonymous):

do you have to put the fractions over the same denominator? or can you just add straight across?

OpenStudy (amistre64):

i just add straight across and hope for the best lol

OpenStudy (anonymous):

Remarkable. Talk about breaking away from the syllabus..sheesh

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