Question

how do i simplify
4x^2-7x+3
divided by
x^2+5x-6?

Answer 1

we have \[\frac{4x^2-7x+3}{x^2-5x+6}\]
let's divide

(x^2-5x+6)*4=4x^2-20x+24
rewriting the numerator as
4x^2-7x+6=(4x^2-20x+24)+13x-18
so
we have now
\[\frac{(4x^2-20x+24)+13x-18
}{x^2-5x+6}\]
if we simplify we get
\[4+\frac{13x-18
}{x^2-5x+6}\]

Answer 2

is there more simplifying? because thats not one of my options

Answer 3

i wrote the question wrong, the denomenator is supposed to be
x^2+5x-6

Answer 4

then
4(x^2+5x-6)=4x^2+20x-24
so
4x^2-7x+3=(4x^2+20x-24)-27x+27
so
we get
\[4+\frac{-27x+27}{x^2+5x-6}\]

Answer 5

these are my options

Answer 6

\[x^2 + 5x - 6 = (x-1)(x+6)\]
\[4x^2-7x+3 = 4x^2-4x-3x+3=4x(x-1)-3(x-1)=(4x-3)(x-1)\]
So cancelling (x-1) you can see the answer

Answer 7

which answer is it?

Answer 8

\[\frac{4x-3}{x+6}\]