Question

This what I have so far...

Answer 1

f'(x)=4x
x=2 f'(2)=4(2)=8 which is m

x=2 f(2)=2(2)^2+3=11 which is y

(8,11)

y-11=8(x-2)

y=8x-5

what do i do next to find y1 and y2?

Answer 2

you need the equation for the line tangent to the graph. did you find that?

Answer 3

huh?

Answer 4

you found it right?

Answer 5

the tangent line at (2,11) is
\[y=8x-5 \]

Answer 6

so if you want the y value at some other point, replace x by the x value given

Answer 7

16-5=11

Answer 8

yes, and you knew that one to begin with right?

Answer 9

yes

Answer 10

since that is the point you used in the first place to find the line
now replace x by -1 to find another point on the line

Answer 11

-8-5=-13

Answer 12

i guess. was the other x value -1?

Answer 13

yes

Answer 14

if so then you are right.