Question

Decide convergence/divergence
from n=1 to infinity
(2^n+1)/(3^n-1)

Answer 1

converges for sure, and in fact i think the sum is not even 5

Answer 2

ignore the irrelavent -1 and +1 and use the root test, get it right away

Answer 3

It is hard to calculate using root test

Answer 4

not when the index is in the exponent, then it is easy

Answer 5

\[\sqrt[n]{2^n}=2\]!

Answer 6

What to do with +1 and -1?

Answer 7

Still have no idea how to do

Answer 8

if you want...you can use the comparison test

Answer 9

Compare with (2/3)^n?

Answer 10

sure...use the limit comparison test then.